Using the hsxkpasswd Terminal Command (Part 2 of 2) (6 September 2015).hsxkpasswd Without sudo (with perlbrew) (15 December 2015).Crypt::HSXKPasswd on MacOS (File::HomeDir workaround) (4 June 2019).Note: due to problems with another package ( File::HomeDir) this command alone is not enough to get Crypt::HSXKPasswd installed on MacOS ATM (June 2019) — there is an easy workaround. You can install the latest stable release of the perl module and terminal command via CPAN: sudo cpan Crypt::HSXKPasswd The Perl POD Documentation for the Module (including a detailed description of the philosophy and mathematics underlying the module’s design).This new version of the module is hosted and managed on GitHub, and the latest stable release is available via CPAN. Return rs.sort(() => Math.random() > Math.random()).The module has been completely re-written from the ground up in the summer of 2014 to make it more programmer friendly and easier to use. Password=password.split('').sort(function(), () => chars), Hold = (password.length%2=0)?(hold.toUpperCase()):(hold) Ĭharacter += punctuation.charAt( entit圓 ) Var string = "abcdefghijklmnopqrstuvwxyz" //to upperĮntity1 = Math.ceil(string.length * Math.random()*Math.random()) Įntity2 = Math.ceil(numeric.length * Math.random()*Math.random()) Įntit圓 = Math.ceil(punctuation.length * Math.random()*Math.random()) So if you're still on team IE 11 or use end-of-life node versions, you're stuck with using a polyfill, math.round() or a workaround with other types such as BigUInt32Array. Other JS engines are tracked on Can I Use or MDN Compatibility TableĬrypto.getRandomValues() has better support (except for Node):.and finally Safari 15 in September 2021.The final ECMAScript 2020 specification (ES11) in June 2020.Edge 79 in January 2020 (the first stable Chromium-based Edge release).Prompt('Here is your shiny new random string:', Personally, I have this little bookmarklet saved in my browser bookmarks bar, for quick and easy access whenever I need to generate a site-specific username: The idea here is to split the generated string into an array of characters, and then sort that character array with cryptographical randomness, and finally joining it back into a string. You may also optionally shuffle the final order, which is easily accomplished with this chaining "oneliner" password.split('').sort( If you specifically want "special characters" included, you can optionally replace the 0-9 numbers in the uppercase stanzas with a simple replace() call. I generally use 4, which gives me rougly 48-52 random alphanumeric characters, upper and lower cased. Length is the number of 64 bit words to join. Index % 2 ? curr.toString(36).toUpperCase() : curr.toString(36) Or we could make a fancy generic generator which uses Array.reduce to concatenate multiple random 64 bit words, alternating between uppercasing each stanza: (new BigUint64Array(length)).reduce( We could do this either by just repeating the process twice: let strings = (new BigUint64Array(2)) Ĭonsole.log(strings.toString(36) + strings.toString(36).toUpperCase()) However, to make it more secure we also want it to be longer and with mixed upper and lower cases. It should give you a truly random string roughly 10-13 characters long. Here we are generating 1 word with 64 bits of random data, and cast it to a base36 string (0-9 and a-z). The idea is the same, we're just utilizing window.crypto instead. However, for reference (and everyone else), I'll show a solution based on an actual CSPRNG. Since you only want passwords 8 characters long, I assume you're not interested in this in any case. Though, please be aware that Math.random() was never designed or meant to be cryptographically secure. Though, you could solve this by simply concatenating two strings, and then slice it back down to 8 characters again. If you are running in an old pre-2016 chrome or pre-2017 safari browser, this might mean (in worst case scenario) you get a shorter password than 8 characters. ![]() However, please be aware that different browsers and javascript implementations used to give different bit depth results for Math.random(). ![]() ![]() The idea is to cast a random number (in the range 0.1) to a base36 string (lowercase a-z plus 0-9), and then fetch the first 8 characters after the leading zero and decimal point. Real Quick-n-dirty™ Math.random().toString(36).slice(2, 10)
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